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4a^2-a-9=0
We add all the numbers together, and all the variables
4a^2-1a-9=0
a = 4; b = -1; c = -9;
Δ = b2-4ac
Δ = -12-4·4·(-9)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{145}}{2*4}=\frac{1-\sqrt{145}}{8} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{145}}{2*4}=\frac{1+\sqrt{145}}{8} $
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